What are the solutions to the equation 2y^2-5y-3=0 ?

The solutions to the equation 2y^2-5y-3=0 are y=3,y=-1/2

Find the zeros of 2y^2-5y-3=0

The zeros of 2y^2-5y-3=0 are y=3,y=-1/2

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2 y^{2} - 5 y - 3 = 0

y = 3, y = - \frac{1}{2}

Decimal Notation

y = 3, y = - 0.5

Solution steps

2 y^{2} - 5 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

y_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, y_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

y = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

y = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

y = 3, y = - \frac{1}{2}

6 x^{2} - 12 x - 2

9 x^{2} - 72 x = 0

x^{2} - \frac{6}{7} x + 2

x, x^{2} - 2 x y + 3 y^{2} = 4

y^{2} - 2 y = 15

What are the solutions to the equation 2y^2-5y-3=0 ?
The solutions to the equation 2y^2-5y-3=0 are y=3,y=-1/2
Find the zeros of 2y^2-5y-3=0
The zeros of 2y^2-5y-3=0 are y=3,y=-1/2