What are the solutions to the equation 10x^2+31x+15=0 ?

The solutions to the equation 10x^2+31x+15=0 are x=-3/5 ,x=-5/2

Find the zeros of 10x^2+31x+15=0

The zeros of 10x^2+31x+15=0 are x=-3/5 ,x=-5/2

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10 x^{2} + 31 x + 15 = 0

x = - \frac{3}{5}, x = - \frac{5}{2}

Decimal Notation

x = - 0.6, x = - 2.5

Solution steps

10 x^{2} + 31 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 10 \cdot 15}{2 \cdot 10}

3 1^{2} - 4 \cdot 10 \cdot 15 = 19

x_{1, 2} = \frac{- 31 \pm 19}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 31 + 19}{2 \cdot 10}, x_{2} = \frac{- 31 - 19}{2 \cdot 10}

x = \frac{- 31 + 19}{2 \cdot 10} : - \frac{3}{5}

x = \frac{- 31 - 19}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{5}, x = - \frac{5}{2}

(x + 5)^{2} = 2

k^{2} - 16 = 0

b, A = \frac{1}{6} b^{2} c

x^{2} - 6 x + 8 = 0

y^{2} - 8 y

What are the solutions to the equation 10x^2+31x+15=0 ?
The solutions to the equation 10x^2+31x+15=0 are x=-3/5 ,x=-5/2
Find the zeros of 10x^2+31x+15=0
The zeros of 10x^2+31x+15=0 are x=-3/5 ,x=-5/2