What are the solutions to the equation 6^2+2^2=x^2 ?

The solutions to the equation 6^2+2^2=x^2 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 6^2+2^2=x^2

The zeros of 6^2+2^2=x^2 are x=2sqrt(10),x=-2sqrt(10)

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6^{2} + 2^{2} = x^{2}

x = 210, x = - 210

Decimal Notation

x = 6.32455 \dots, x = - 6.32455 \dots

Solution steps

6^{2} + 2^{2} = x^{2}

Switch sides

x^{2} = 6^{2} + 2^{2}

Simplify

6^{2} + 2^{2} : 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

y^{2} + 11 y + 10 = 0

24 x = - 48 - 3 x^{2}

x^{2} + 9^{2} = 1 0^{2}

x^{2} - 96 = 20 x

x, x^{2} + y^{2} + 10 y + 25 = 0

What are the solutions to the equation 6^2+2^2=x^2 ?
The solutions to the equation 6^2+2^2=x^2 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 6^2+2^2=x^2
The zeros of 6^2+2^2=x^2 are x=2sqrt(10),x=-2sqrt(10)