What are the solutions to the equation x^2+13x+43=11 ?

The solutions to the equation x^2+13x+43=11 are x=(-13+sqrt(41))/2 ,x=(-13-sqrt(41))/2

Find the zeros of x^2+13x+43=11

The zeros of x^2+13x+43=11 are x=(-13+sqrt(41))/2 ,x=(-13-sqrt(41))/2

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x^{2} + 13 x + 43 = 11

x = \frac{- 13 + 41}{2}, x = \frac{- 13 - 41}{2}

Decimal Notation

x = - 3.29843 \dots, x = - 9.70156 \dots

Solution steps

x^{2} + 13 x + 43 = 11

Move

11

to the left side

x^{2} + 13 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 32 = 41

x_{1, 2} = \frac{- 13 \pm 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 41}{2 \cdot 1}, x_{2} = \frac{- 13 - 41}{2 \cdot 1}

x = \frac{- 13 + 41}{2 \cdot 1} : \frac{- 13 + 41}{2}

x = \frac{- 13 - 41}{2 \cdot 1} : \frac{- 13 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 41}{2}, x = \frac{- 13 - 41}{2}

p, \frac{x p ^{2}}{x q ^{2}} = (x^{50})^{2}

0 = - 2 (x - 2)^{2} + 3

x^{2} + x + 3

4 x^{2} + 12 x = 18

0 = 2 x^{2} - 10 x + 8

What are the solutions to the equation x^2+13x+43=11 ?
The solutions to the equation x^2+13x+43=11 are x=(-13+sqrt(41))/2 ,x=(-13-sqrt(41))/2
Find the zeros of x^2+13x+43=11
The zeros of x^2+13x+43=11 are x=(-13+sqrt(41))/2 ,x=(-13-sqrt(41))/2