What are the solutions to the equation 0=-2(x-2)^2+3 ?

The solutions to the equation 0=-2(x-2)^2+3 are x=sqrt(3/2)+2,x=-sqrt(3/2)+2

Find the zeros of 0=-2(x-2)^2+3

The zeros of 0=-2(x-2)^2+3 are x=sqrt(3/2)+2,x=-sqrt(3/2)+2

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0 = - 2 (x - 2)^{2} + 3

x = \frac{3}{2} + 2, x = - \frac{3}{2} + 2

Decimal Notation

x = 3.22474 \dots, x = 0.77525 \dots

Solution steps

0 = - 2 (x - 2)^{2} + 3

Switch sides

- 2 (x - 2)^{2} + 3 = 0

Move

3

to the right side

- 2 (x - 2)^{2} = - 3

Divide both sides by

- 2

(x - 2)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = \frac{3}{2} : x = \frac{3}{2} + 2

Solve

x - 2 = - \frac{3}{2} : x = - \frac{3}{2} + 2

The solutions to the quadratic equation are:

x = \frac{3}{2} + 2, x = - \frac{3}{2} + 2

x^{2} + x + 3

4 x^{2} + 12 x = 18

0 = 2 x^{2} - 10 x + 8

5 x^{2} = - 30 x - 65

x^{2} + 4 x - 25 = 0

What are the solutions to the equation 0=-2(x-2)^2+3 ?
The solutions to the equation 0=-2(x-2)^2+3 are x=sqrt(3/2)+2,x=-sqrt(3/2)+2
Find the zeros of 0=-2(x-2)^2+3
The zeros of 0=-2(x-2)^2+3 are x=sqrt(3/2)+2,x=-sqrt(3/2)+2