What are the solutions to the equation (1/4)^2+y^2=1 ?

The solutions to the equation (1/4)^2+y^2=1 are y=(sqrt(15))/4 ,y=-(sqrt(15))/4

Find the zeros of (1/4)^2+y^2=1

The zeros of (1/4)^2+y^2=1 are y=(sqrt(15))/4 ,y=-(sqrt(15))/4

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(\frac{1}{4})^{2} + y^{2} = 1

y = \frac{15}{4}, y = - \frac{15}{4}

Decimal Notation

y = 0.96824 \dots, y = - 0.96824 \dots

Solution steps

(\frac{1}{4})^{2} + y^{2} = 1

Expand

(\frac{1}{4})^{2} + y^{2} : \frac{1}{16} + y^{2}

\frac{1}{16} + y^{2} = 1

Move

\frac{1}{16}

to the right side

y^{2} = 1 - \frac{1}{16}

Simplify

1 - \frac{1}{16} : \frac{15}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{15}{16}, y = - \frac{15}{16}

\frac{15}{16} = \frac{15}{4}

- \frac{15}{16} = - \frac{15}{4}

y = \frac{15}{4}, y = - \frac{15}{4}

y, x^{2} + y^{2} = 64

\frac{x - 3 ( x - 1 )}{2} = \frac{( x - 1 ) ^{2}}{2}

0 = x^{2} + 6 x + 10

6 x^{2} - 9 x + 1 = x

2 (x - 9)^{2} + 8 = 0

What are the solutions to the equation (1/4)^2+y^2=1 ?
The solutions to the equation (1/4)^2+y^2=1 are y=(sqrt(15))/4 ,y=-(sqrt(15))/4
Find the zeros of (1/4)^2+y^2=1
The zeros of (1/4)^2+y^2=1 are y=(sqrt(15))/4 ,y=-(sqrt(15))/4