What are the solutions to the equation 2x^2-250x+5000=0 ?

The solutions to the equation 2x^2-250x+5000=0 are x=100,x=25

Find the zeros of 2x^2-250x+5000=0

The zeros of 2x^2-250x+5000=0 are x=100,x=25

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2 x^{2} - 250 x + 5000 = 0

x = 100, x = 25

Solution steps

2 x^{2} - 250 x + 5000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 250 ) \pm ( - 250 ) ^{2} - 4 \cdot 2 \cdot 5000}{2 \cdot 2}

(- 250)^{2} - 4 \cdot 2 \cdot 5000 = 150

x_{1, 2} = \frac{- ( - 250 ) \pm 150}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 250 ) + 150}{2 \cdot 2}, x_{2} = \frac{- ( - 250 ) - 150}{2 \cdot 2}

x = \frac{- ( - 250 ) + 150}{2 \cdot 2} : 100

x = \frac{- ( - 250 ) - 150}{2 \cdot 2} : 25

The solutions to the quadratic equation are:

x = 100, x = 25

62.5 = 10 (b)^{2}

x, x^{2} + 2 x + 5 = 0

b, A = \frac{1}{2} h (b^{1} + b^{2})

2 x^{2} - 8 x - 8 = 0

x^{2} - 8 x + 12 = 0

What are the solutions to the equation 2x^2-250x+5000=0 ?
The solutions to the equation 2x^2-250x+5000=0 are x=100,x=25
Find the zeros of 2x^2-250x+5000=0
The zeros of 2x^2-250x+5000=0 are x=100,x=25