What are the solutions to the equation 3x^2+5x=-1 ?

The solutions to the equation 3x^2+5x=-1 are x=(-5+sqrt(13))/6 ,x=(-5-sqrt(13))/6

Find the zeros of 3x^2+5x=-1

The zeros of 3x^2+5x=-1 are x=(-5+sqrt(13))/6 ,x=(-5-sqrt(13))/6

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3 x^{2} + 5 x = - 1

x = \frac{- 5 + 13}{6}, x = \frac{- 5 - 13}{6}

Decimal Notation

x = - 0.23240 \dots, x = - 1.43425 \dots

Solution steps

3 x^{2} + 5 x = - 1

Move

1

to the left side

3 x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

5^{2} - 4 \cdot 3 \cdot 1 = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 3}, x_{2} = \frac{- 5 - 13}{2 \cdot 3}

x = \frac{- 5 + 13}{2 \cdot 3} : \frac{- 5 + 13}{6}

x = \frac{- 5 - 13}{2 \cdot 3} : \frac{- 5 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{6}, x = \frac{- 5 - 13}{6}

x^{2} + 3 = 6 x

3 x^{2} + 42 x = - 24

9 - x^{2} = x^{2} + 1

7 x^{2} - 9 x + 12 = 5 x^{2} - 6

1 2^{2} = 6^{2} + x^{2}

What are the solutions to the equation 3x^2+5x=-1 ?
The solutions to the equation 3x^2+5x=-1 are x=(-5+sqrt(13))/6 ,x=(-5-sqrt(13))/6
Find the zeros of 3x^2+5x=-1
The zeros of 3x^2+5x=-1 are x=(-5+sqrt(13))/6 ,x=(-5-sqrt(13))/6