What are the solutions to the equation 3(x+3)^2=36 ?

The solutions to the equation 3(x+3)^2=36 are x=2sqrt(3)-3,x=-2sqrt(3)-3

Find the zeros of 3(x+3)^2=36

The zeros of 3(x+3)^2=36 are x=2sqrt(3)-3,x=-2sqrt(3)-3

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3 (x + 3)^{2} = 36

x = 23 - 3, x = - 23 - 3

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

3 (x + 3)^{2} = 36

Divide both sides by

3

(x + 3)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 12 : x = 23 - 3

Solve

x + 3 = - 12 : x = - 23 - 3

The solutions to the quadratic equation are:

x = 23 - 3, x = - 23 - 3

5 x^{2} + 20 x + 15 = 0

3 (x - 2)^{2} + 3 = 6 x - 12

3 x^{2} - 6 x + 2 = 0

x^{2} - 11 x - 80 = 0

f, y = (f)^{2}

What are the solutions to the equation 3(x+3)^2=36 ?
The solutions to the equation 3(x+3)^2=36 are x=2sqrt(3)-3,x=-2sqrt(3)-3
Find the zeros of 3(x+3)^2=36
The zeros of 3(x+3)^2=36 are x=2sqrt(3)-3,x=-2sqrt(3)-3