What are the solutions to the equation 6(5x-4)(3x+5)=0 ?

The solutions to the equation 6(5x-4)(3x+5)=0 are x= 4/5 ,x=-5/3

Find the zeros of 6(5x-4)(3x+5)=0

The zeros of 6(5x-4)(3x+5)=0 are x= 4/5 ,x=-5/3

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6 (5 x - 4) (3 x + 5) = 0

x = \frac{4}{5}, x = - \frac{5}{3}

Decimal Notation

x = 0.8, x = - 1.66666 \dots

Solution steps

6 (5 x - 4) (3 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 4 = 0 or 3 x + 5 = 0

Solve

5 x - 4 = 0 : x = \frac{4}{5}

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - \frac{5}{3}

5 x^{2} + 12 x = - 3 x

- 5 x^{2} + 5 x + 2 = 0

- x^{2} + 6 x + 1 = 0

x^{2} + 6 x = - 22

- 16 x^{2} + 64 x + 48 = 0

What are the solutions to the equation 6(5x-4)(3x+5)=0 ?
The solutions to the equation 6(5x-4)(3x+5)=0 are x= 4/5 ,x=-5/3
Find the zeros of 6(5x-4)(3x+5)=0
The zeros of 6(5x-4)(3x+5)=0 are x= 4/5 ,x=-5/3