What are the solutions to the equation x^2+6x=-22 ?

The solutions to the equation x^2+6x=-22 are x=-3+sqrt(13)i,x=-3-sqrt(13)i

Find the zeros of x^2+6x=-22

The zeros of x^2+6x=-22 are x=-3+sqrt(13)i,x=-3-sqrt(13)i

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x^{2} + 6 x = - 22

x = - 3 + 13 i, x = - 3 - 13 i

Solution steps

x^{2} + 6 x = - 22

Move

22

to the left side

x^{2} + 6 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 22 : 213 i

x_{1, 2} = \frac{- 6 \pm 2 13 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 13 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 13 i}{2 \cdot 1}

x = \frac{- 6 + 2 13 i}{2 \cdot 1} : - 3 + 13 i

x = \frac{- 6 - 2 13 i}{2 \cdot 1} : - 3 - 13 i

The solutions to the quadratic equation are:

x = - 3 + 13 i, x = - 3 - 13 i

- 16 x^{2} + 64 x + 48 = 0

y, y^{2} = x^{2} (x + 5)

x^{2} - 3 x = 30

3 x^{2} + 48 x + 183 = 0

x^{2} - 2 x - 3 = 0

What are the solutions to the equation x^2+6x=-22 ?
The solutions to the equation x^2+6x=-22 are x=-3+sqrt(13)i,x=-3-sqrt(13)i
Find the zeros of x^2+6x=-22
The zeros of x^2+6x=-22 are x=-3+sqrt(13)i,x=-3-sqrt(13)i