What are the solutions to the equation a^2+1=2 ?

The solutions to the equation a^2+1=2 are a=1,a=-1

Find the zeros of a^2+1=2

The zeros of a^2+1=2 are a=1,a=-1

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a^{2} + 1 = 2

a = 1, a = - 1

Solution steps

a^{2} + 1 = 2

Move

1

to the right side

a^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 1, a = - 1

1 = 1

- 1 = - 1

a = 1, a = - 1

5 x^{2} + 80 x = - 270

5 x^{2} - 10 x - 8 = 0

y, 2 x^{2} y + \frac{( x ^{3} - y ^{2} )}{x} + 3 = 0

- x^{2} + 3 x + 1 = 0

x^{2} - 10 x + 24

What are the solutions to the equation a^2+1=2 ?
The solutions to the equation a^2+1=2 are a=1,a=-1
Find the zeros of a^2+1=2
The zeros of a^2+1=2 are a=1,a=-1