What are the solutions to the equation m^2+5m=2 ?

The solutions to the equation m^2+5m=2 are m=(-5+sqrt(33))/2 ,m=(-5-sqrt(33))/2

Find the zeros of m^2+5m=2

The zeros of m^2+5m=2 are m=(-5+sqrt(33))/2 ,m=(-5-sqrt(33))/2

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m^{2} + 5 m = 2

m = \frac{- 5 + 33}{2}, m = \frac{- 5 - 33}{2}

Decimal Notation

m = 0.37228 \dots, m = - 5.37228 \dots

Solution steps

m^{2} + 5 m = 2

Move

2

to the left side

m^{2} + 5 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 2) = 33

m_{1, 2} = \frac{- 5 \pm 33}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 5 + 33}{2 \cdot 1}, m_{2} = \frac{- 5 - 33}{2 \cdot 1}

m = \frac{- 5 + 33}{2 \cdot 1} : \frac{- 5 + 33}{2}

m = \frac{- 5 - 33}{2 \cdot 1} : \frac{- 5 - 33}{2}

The solutions to the quadratic equation are:

m = \frac{- 5 + 33}{2}, m = \frac{- 5 - 33}{2}

x, 9 x^{2} + 24 x y + 16 y^{2} + 90 x - 130 y = 0

x^{2} + 9 x - 46 = 7 x + 2

0.2 w^{2} - 0.3 w = 20

x^{2} - x + \frac{5}{4} = 0

x (x - 16) - 20 = - 3

What are the solutions to the equation m^2+5m=2 ?
The solutions to the equation m^2+5m=2 are m=(-5+sqrt(33))/2 ,m=(-5-sqrt(33))/2
Find the zeros of m^2+5m=2
The zeros of m^2+5m=2 are m=(-5+sqrt(33))/2 ,m=(-5-sqrt(33))/2