What are the solutions to the equation 2x^2+26x+80=0 ?

The solutions to the equation 2x^2+26x+80=0 are x=-5,x=-8

Find the zeros of 2x^2+26x+80=0

The zeros of 2x^2+26x+80=0 are x=-5,x=-8

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2 x^{2} + 26 x + 80 = 0

x = - 5, x = - 8

Solution steps

2 x^{2} + 26 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 2 \cdot 80}{2 \cdot 2}

2 6^{2} - 4 \cdot 2 \cdot 80 = 6

x_{1, 2} = \frac{- 26 \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 26 + 6}{2 \cdot 2}, x_{2} = \frac{- 26 - 6}{2 \cdot 2}

x = \frac{- 26 + 6}{2 \cdot 2} : - 5

x = \frac{- 26 - 6}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = - 5, x = - 8

2 x^{2} + 8 = 26

x^{2} - 4 x - 1 = 0

x^{2} + 10 x - 8 = 0

- \frac{7}{2} x^{2} + 3 x + \frac{8}{3}

(x + 1)^{2} + 2 x = 3 x (x + 1) + 5

What are the solutions to the equation 2x^2+26x+80=0 ?
The solutions to the equation 2x^2+26x+80=0 are x=-5,x=-8
Find the zeros of 2x^2+26x+80=0
The zeros of 2x^2+26x+80=0 are x=-5,x=-8