What are the solutions to the equation -3x^2+168x+1=2326 ?

The solutions to the equation -3x^2+168x+1=2326 are x=25,x=31

Find the zeros of -3x^2+168x+1=2326

The zeros of -3x^2+168x+1=2326 are x=25,x=31

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- 3 x^{2} + 168 x + 1 = 2326

x = 25, x = 31

Solution steps

- 3 x^{2} + 168 x + 1 = 2326

Move

2326

to the left side

- 3 x^{2} + 168 x - 2325 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 168 \pm 16 8 ^{2} - 4 ( - 3 ) ( - 2325 )}{2 ( - 3 )}

16 8^{2} - 4 (- 3) (- 2325) = 18

x_{1, 2} = \frac{- 168 \pm 18}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 168 + 18}{2 ( - 3 )}, x_{2} = \frac{- 168 - 18}{2 ( - 3 )}

x = \frac{- 168 + 18}{2 ( - 3 )} : 25

x = \frac{- 168 - 18}{2 ( - 3 )} : 31

The solutions to the quadratic equation are:

x = 25, x = 31

x, f = x^{2} + 3 y

x, x^{2} + 5 x + 6 = 0

16 x^{2} + 64 x + 65 = 0

4 x^{2} - 31 = 49

9 s^{2} + 6 s + 1 = 0

What are the solutions to the equation -3x^2+168x+1=2326 ?
The solutions to the equation -3x^2+168x+1=2326 are x=25,x=31
Find the zeros of -3x^2+168x+1=2326
The zeros of -3x^2+168x+1=2326 are x=25,x=31