What are the solutions to the equation 3x^2-12x-135=0 ?

The solutions to the equation 3x^2-12x-135=0 are x=9,x=-5

Find the zeros of 3x^2-12x-135=0

The zeros of 3x^2-12x-135=0 are x=9,x=-5

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3 x^{2} - 12 x - 135 = 0

x = 9, x = - 5

Solution steps

3 x^{2} - 12 x - 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 135 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 135) = 42

x_{1, 2} = \frac{- ( - 12 ) \pm 42}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 42}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 42}{2 \cdot 3}

x = \frac{- ( - 12 ) + 42}{2 \cdot 3} : 9

x = \frac{- ( - 12 ) - 42}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = 9, x = - 5

2 x^{2} + 10 x + 6 = 0

6 x^{2} - 60 x + 126 = 0

7 x^{2} + 4 x - 1 = 0

x, x^{2} + y^{2} + z^{2} = 8

x, x^{2} + y^{2} + z^{2} = 6

What are the solutions to the equation 3x^2-12x-135=0 ?
The solutions to the equation 3x^2-12x-135=0 are x=9,x=-5
Find the zeros of 3x^2-12x-135=0
The zeros of 3x^2-12x-135=0 are x=9,x=-5