What are the solutions to the equation (3x-1)(x-1)=96 ?

The solutions to the equation (3x-1)(x-1)=96 are x= 19/3 ,x=-5

Find the zeros of (3x-1)(x-1)=96

The zeros of (3x-1)(x-1)=96 are x= 19/3 ,x=-5

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(3 x - 1) (x - 1) = 96

x = \frac{19}{3}, x = - 5

Decimal Notation

x = 6.33333 \dots, x = - 5

Solution steps

(3 x - 1) (x - 1) = 96

Expand

(3 x - 1) (x - 1) : 3 x^{2} - 4 x + 1

3 x^{2} - 4 x + 1 = 96

Move

96

to the left side

3 x^{2} - 4 x - 95 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 95 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 95) = 34

x_{1, 2} = \frac{- ( - 4 ) \pm 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 34}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 34}{2 \cdot 3}

x = \frac{- ( - 4 ) + 34}{2 \cdot 3} : \frac{19}{3}

x = \frac{- ( - 4 ) - 34}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{19}{3}, x = - 5

- 5 x^{2} + 6 x + 14 = - 5

5 x^{2} + 6 x + 9 = 0

(x + 4)^{2} = 28

(x + 4)^{2} = 20

5 x^{2} + 6 x + 4 = 0

What are the solutions to the equation (3x-1)(x-1)=96 ?
The solutions to the equation (3x-1)(x-1)=96 are x= 19/3 ,x=-5
Find the zeros of (3x-1)(x-1)=96
The zeros of (3x-1)(x-1)=96 are x= 19/3 ,x=-5