What are the solutions to the equation solvefor c,(c+y)(c-y)=(3c^2-y)y ?

The solutions to the equation solvefor c,(c+y)(c-y)=(3c^2-y)y are c=0

Find the zeros of solvefor c,(c+y)(c-y)=(3c^2-y)y

The zeros of solvefor c,(c+y)(c-y)=(3c^2-y)y are c=0

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solve for

c, (c + y) (c - y) = (3 c^{2} - y) y

c = 0

Solution steps

(c + y) (c - y) = (3 c^{2} - y) y

Expand

(c + y) (c - y) : c^{2} - y^{2}

Expand

(3 c^{2} - y) y : 3 c^{2} y - y^{2}

c^{2} - y^{2} = 3 c^{2} y - y^{2}

Move

y^{2}

to the right side

c^{2} = 3 c^{2} y

Move

3 c^{2} y

to the left side

c^{2} - 3 c^{2} y = 0

Factor

c^{2} - 3 c^{2} y : c^{2} (1 - 3 y)

c^{2} (1 - 3 y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c^{2} = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

c = 0

1 8^{2} + b^{2} = 3 0^{2}

x (x + 3) = 270

a^{2} + 2 a + 3 = 0

x^{2} + (n + 3) x + n + 2 = 0

f, f = f (x + 2) - 3

What are the solutions to the equation solvefor c,(c+y)(c-y)=(3c^2-y)y ?
The solutions to the equation solvefor c,(c+y)(c-y)=(3c^2-y)y are c=0
Find the zeros of solvefor c,(c+y)(c-y)=(3c^2-y)y
The zeros of solvefor c,(c+y)(c-y)=(3c^2-y)y are c=0