What are the solutions to the equation a^2+2a+3=0 ?

The solutions to the equation a^2+2a+3=0 are a=-1+sqrt(2)i,a=-1-sqrt(2)i

Find the zeros of a^2+2a+3=0

The zeros of a^2+2a+3=0 are a=-1+sqrt(2)i,a=-1-sqrt(2)i

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a^{2} + 2 a + 3 = 0

a = - 1 + 2 i, a = - 1 - 2 i

Solution steps

a^{2} + 2 a + 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

a_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, a_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

a = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

a = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

a = - 1 + 2 i, a = - 1 - 2 i

x^{2} + (n + 3) x + n + 2 = 0

f, f = f (x + 2) - 3

x^{2} + 9 = 8 x

x, x^{2} y + y^{2} x = 6

p, x^{2} p^{2} + x y p - 6 y^{2} = 0

What are the solutions to the equation a^2+2a+3=0 ?
The solutions to the equation a^2+2a+3=0 are a=-1+sqrt(2)i,a=-1-sqrt(2)i
Find the zeros of a^2+2a+3=0
The zeros of a^2+2a+3=0 are a=-1+sqrt(2)i,a=-1-sqrt(2)i