What are the solutions to the equation x^2+8x+16=36 ?

The solutions to the equation x^2+8x+16=36 are x=2,x=-10

Find the zeros of x^2+8x+16=36

The zeros of x^2+8x+16=36 are x=2,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x + 16 = 36

x = 2, x = - 10

Solution steps

x^{2} + 8 x + 16 = 36

Move

36

to the left side

x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 1}, x_{2} = \frac{- 8 - 12}{2 \cdot 1}

x = \frac{- 8 + 12}{2 \cdot 1} : 2

x = \frac{- 8 - 12}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

- 2 x^{2} + 6 x + 5 = 0

1 + 4 + 7 + (3 n - 2) = \frac{n ( 3 n - 1 )}{2}

x, x^{2} - k x + 121 = 0

n^{2} + n = 0

20 x^{2} + 40 x = 0

What are the solutions to the equation x^2+8x+16=36 ?
The solutions to the equation x^2+8x+16=36 are x=2,x=-10
Find the zeros of x^2+8x+16=36
The zeros of x^2+8x+16=36 are x=2,x=-10