What are the solutions to the equation 15x^2-4x-126=-30 ?

The solutions to the equation 15x^2-4x-126=-30 are x= 8/3 ,x=-12/5

Find the zeros of 15x^2-4x-126=-30

The zeros of 15x^2-4x-126=-30 are x= 8/3 ,x=-12/5

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15 x^{2} - 4 x - 126 = - 30

x = \frac{8}{3}, x = - \frac{12}{5}

Solution steps

15 x^{2} - 4 x - 126 = - 30

Move

30

to the left side

15 x^{2} - 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 15 ( - 96 )}{2 \cdot 15}

(- 4)^{2} - 4 \cdot 15 (- 96) = 76

x_{1, 2} = \frac{- ( - 4 ) \pm 76}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 76}{2 \cdot 15}, x_{2} = \frac{- ( - 4 ) - 76}{2 \cdot 15}

x = \frac{- ( - 4 ) + 76}{2 \cdot 15} : \frac{8}{3}

x = \frac{- ( - 4 ) - 76}{2 \cdot 15} : - \frac{12}{5}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - \frac{12}{5}

\frac{k ^{2}}{1.2 - 7} = 23

x^{2} - 4 + 3 = 0

6 x^{2} - 2 x = 20

0 = x^{2} + 9

x^{2} + 3 x - 1 = x - 2 x^{2}

What are the solutions to the equation 15x^2-4x-126=-30 ?
The solutions to the equation 15x^2-4x-126=-30 are x= 8/3 ,x=-12/5
Find the zeros of 15x^2-4x-126=-30
The zeros of 15x^2-4x-126=-30 are x= 8/3 ,x=-12/5