What are the solutions to the equation 2x+x^2=-13 ?

The solutions to the equation 2x+x^2=-13 are x=-1+2sqrt(3)i,x=-1-2sqrt(3)i

Find the zeros of 2x+x^2=-13

The zeros of 2x+x^2=-13 are x=-1+2sqrt(3)i,x=-1-2sqrt(3)i

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2 x + x^{2} = - 13

x = - 1 + 23 i, x = - 1 - 23 i

Solution steps

2 x + x^{2} = - 13

Move

13

to the left side

2 x + x^{2} + 13 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 13 : 43 i

x_{1, 2} = \frac{- 2 \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 3 i}{2 \cdot 1}

x = \frac{- 2 + 4 3 i}{2 \cdot 1} : - 1 + 23 i

x = \frac{- 2 - 4 3 i}{2 \cdot 1} : - 1 - 23 i

The solutions to the quadratic equation are:

x = - 1 + 23 i, x = - 1 - 23 i

6 x^{2} - 16 x - 6 = 0

10 x^{2} + 25 x = 15

- 3 x^{2} - 6 x - 5 = 0

5 x^{2} - 36 = 0

- 16 t^{2} + 16 t + 32 = 0

What are the solutions to the equation 2x+x^2=-13 ?
The solutions to the equation 2x+x^2=-13 are x=-1+2sqrt(3)i,x=-1-2sqrt(3)i
Find the zeros of 2x+x^2=-13
The zeros of 2x+x^2=-13 are x=-1+2sqrt(3)i,x=-1-2sqrt(3)i