What are the solutions to the equation 4x^2+48=0 ?

The solutions to the equation 4x^2+48=0 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of 4x^2+48=0

The zeros of 4x^2+48=0 are x=2sqrt(3)i,x=-2sqrt(3)i

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4 x^{2} + 48 = 0

x = 23 i, x = - 23 i

Solution steps

4 x^{2} + 48 = 0

Move

48

to the right side

4 x^{2} = - 48

Divide both sides by

4

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

k^{2} + k - 2 = 0

4000 (1 + r)^{2} + 1000 (1 + r) = 5941.23

t^{2} - 4 t - 5 = 0

21 - 3 x^{2} = 0

2 x^{2} - 8 x - 10 = x + 8

What are the solutions to the equation 4x^2+48=0 ?
The solutions to the equation 4x^2+48=0 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of 4x^2+48=0
The zeros of 4x^2+48=0 are x=2sqrt(3)i,x=-2sqrt(3)i