What are the solutions to the equation -4.9t^2+31t=0 ?

The solutions to the equation -4.9t^2+31t=0 are t=0,t= 310/49

Find the zeros of -4.9t^2+31t=0

The zeros of -4.9t^2+31t=0 are t=0,t= 310/49

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- 4.9 t^{2} + 31 t = 0

t = 0, t = \frac{310}{49}

Solution steps

- 4.9 t^{2} + 31 t = 0

Multiply both sides by

10

- 49 t^{2} + 310 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 310 \pm 31 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

31 0^{2} - 4 (- 49) \cdot 0 = 310

t_{1, 2} = \frac{- 310 \pm 310}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 310 + 310}{2 ( - 49 )}, t_{2} = \frac{- 310 - 310}{2 ( - 49 )}

t = \frac{- 310 + 310}{2 ( - 49 )} : 0

t = \frac{- 310 - 310}{2 ( - 49 )} : \frac{310}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{310}{49}

x^{2} - 11 x - 28 = 0

- 2 x^{2} + 6 x - 5 = 0

x^{2} + 2 x = - 13

3 s^{2} - 2 s = - 5

(x - 2) (x - 7) = 0

What are the solutions to the equation -4.9t^2+31t=0 ?
The solutions to the equation -4.9t^2+31t=0 are t=0,t= 310/49
Find the zeros of -4.9t^2+31t=0
The zeros of -4.9t^2+31t=0 are t=0,t= 310/49