What are the solutions to the equation (x-2)(x-5)=6 ?

The solutions to the equation (x-2)(x-5)=6 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

Find the zeros of (x-2)(x-5)=6

The zeros of (x-2)(x-5)=6 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

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(x - 2) (x - 5) = 6

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

Decimal Notation

x = 6.37228 \dots, x = 0.62771 \dots

Solution steps

(x - 2) (x - 5) = 6

Expand

(x - 2) (x - 5) : x^{2} - 7 x + 10

x^{2} - 7 x + 10 = 6

Move

6

to the left side

x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 4 = 33

x_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 1}

x = \frac{- ( - 7 ) + 33}{2 \cdot 1} : \frac{7 + 33}{2}

x = \frac{- ( - 7 ) - 33}{2 \cdot 1} : \frac{7 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

x^{2} - 5 x + 6

- 4 x^{2} + 8 x - 3 = 0

(4 x - 5)^{2} = 25

b (b + 5) = 0

0.000006 x^{2} - 0.02 x + 25 = 28

What are the solutions to the equation (x-2)(x-5)=6 ?
The solutions to the equation (x-2)(x-5)=6 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2
Find the zeros of (x-2)(x-5)=6
The zeros of (x-2)(x-5)=6 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2