What are the solutions to the equation -4x^2+8x-3=0 ?

The solutions to the equation -4x^2+8x-3=0 are x= 1/2 ,x= 3/2

Find the zeros of -4x^2+8x-3=0

The zeros of -4x^2+8x-3=0 are x= 1/2 ,x= 3/2

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- 4 x^{2} + 8 x - 3 = 0

x = \frac{1}{2}, x = \frac{3}{2}

Solution steps

- 4 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

8^{2} - 4 (- 4) (- 3) = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 ( - 4 )}, x_{2} = \frac{- 8 - 4}{2 ( - 4 )}

x = \frac{- 8 + 4}{2 ( - 4 )} : \frac{1}{2}

x = \frac{- 8 - 4}{2 ( - 4 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{3}{2}

(4 x - 5)^{2} = 25

b (b + 5) = 0

0.000006 x^{2} - 0.02 x + 25 = 28

(x + 1)^{3} - (x - 1)^{3} = 7 x

1^{2} + 3^{2} = x^{2}

What are the solutions to the equation -4x^2+8x-3=0 ?
The solutions to the equation -4x^2+8x-3=0 are x= 1/2 ,x= 3/2
Find the zeros of -4x^2+8x-3=0
The zeros of -4x^2+8x-3=0 are x= 1/2 ,x= 3/2