What are the solutions to the equation (4x-5)^2=25 ?

The solutions to the equation (4x-5)^2=25 are x= 5/2 ,x=0

Find the zeros of (4x-5)^2=25

The zeros of (4x-5)^2=25 are x= 5/2 ,x=0

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(4 x - 5)^{2} = 25

x = \frac{5}{2}, x = 0

Solution steps

(4 x - 5)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 5 = 25 : x = \frac{5}{2}

Solve

4 x - 5 = - 25 : x = 0

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 0

b (b + 5) = 0

0.000006 x^{2} - 0.02 x + 25 = 28

(x + 1)^{3} - (x - 1)^{3} = 7 x

1^{2} + 3^{2} = x^{2}

4 x^{2} - 15 x = 0

What are the solutions to the equation (4x-5)^2=25 ?
The solutions to the equation (4x-5)^2=25 are x= 5/2 ,x=0
Find the zeros of (4x-5)^2=25
The zeros of (4x-5)^2=25 are x= 5/2 ,x=0