What are the solutions to the equation x-2+x(x-6)=4 ?

The solutions to the equation x-2+x(x-6)=4 are x=6,x=-1

Find the zeros of x-2+x(x-6)=4

The zeros of x-2+x(x-6)=4 are x=6,x=-1

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x - 2 + x (x - 6) = 4

x = 6, x = - 1

Solution steps

x - 2 + x (x - 6) = 4

Expand

x - 2 + x (x - 6) : x^{2} - 5 x - 2

x^{2} - 5 x - 2 = 4

Move

4

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

1.2 r^{2} + 5.7 r = 2.3

x^{2} - 4 x + 4 = 75

4 x^{2} + 8 x - 32 = 0

9 x^{2} - 5 x - 7 = 0

(x + 8)^{2} - 4 = - 20

What are the solutions to the equation x-2+x(x-6)=4 ?
The solutions to the equation x-2+x(x-6)=4 are x=6,x=-1
Find the zeros of x-2+x(x-6)=4
The zeros of x-2+x(x-6)=4 are x=6,x=-1