What are the solutions to the equation x^2+3bx-10b^2=0 ?

The solutions to the equation x^2+3bx-10b^2=0 are x=2b,x=-5b

Find the zeros of x^2+3bx-10b^2=0

The zeros of x^2+3bx-10b^2=0 are x=2b,x=-5b

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x^{2} + 3 b x - 10 b^{2} = 0

x = 2 b, x = - 5 b

Solution steps

x^{2} + 3 b x - 10 b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 b \pm ( 3 b ) ^{2} - 4 \cdot 1 \cdot ( - 10 b ^{2} )}{2 \cdot 1}

Simplify

(3 b)^{2} - 4 \cdot 1 \cdot (- 10 b^{2}) : 7 b

x_{1, 2} = \frac{- 3 b \pm 7 b}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 b + 7 b}{2 \cdot 1}, x_{2} = \frac{- 3 b - 7 b}{2 \cdot 1}

x = \frac{- 3 b + 7 b}{2 \cdot 1} : 2 b

x = \frac{- 3 b - 7 b}{2 \cdot 1} : - 5 b

The solutions to the quadratic equation are:

x = 2 b, x = - 5 b

x^{2} = 8^{2} + 1 0^{2}

3 (3 x - 2) = (x + 4) (x - 4)

x^{2} - 5 x - 19 = 0

3 x^{2} - 72 = 6 x

X^{2} - 100 = 0

What are the solutions to the equation x^2+3bx-10b^2=0 ?
The solutions to the equation x^2+3bx-10b^2=0 are x=2b,x=-5b
Find the zeros of x^2+3bx-10b^2=0
The zeros of x^2+3bx-10b^2=0 are x=2b,x=-5b