What are the solutions to the equation x^2-5x-19=0 ?

The solutions to the equation x^2-5x-19=0 are x=(5+sqrt(101))/2 ,x=(5-sqrt(101))/2

Find the zeros of x^2-5x-19=0

The zeros of x^2-5x-19=0 are x=(5+sqrt(101))/2 ,x=(5-sqrt(101))/2

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x^{2} - 5 x - 19 = 0

x = \frac{5 + 101}{2}, x = \frac{5 - 101}{2}

Solution steps

x^{2} - 5 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 19) = 101

x_{1, 2} = \frac{- ( - 5 ) \pm 101}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 101}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 101}{2 \cdot 1}

x = \frac{- ( - 5 ) + 101}{2 \cdot 1} : \frac{5 + 101}{2}

x = \frac{- ( - 5 ) - 101}{2 \cdot 1} : \frac{5 - 101}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 101}{2}, x = \frac{5 - 101}{2}

3 x^{2} - 72 = 6 x

X^{2} - 100 = 0

x^{2} + 12 x + 36 = 5

2 x^{2} + 12 x + \frac{35}{2} = 0

5 x^{2} + 7 x + 1 = 0

What are the solutions to the equation x^2-5x-19=0 ?
The solutions to the equation x^2-5x-19=0 are x=(5+sqrt(101))/2 ,x=(5-sqrt(101))/2
Find the zeros of x^2-5x-19=0
The zeros of x^2-5x-19=0 are x=(5+sqrt(101))/2 ,x=(5-sqrt(101))/2