What are the solutions to the equation x^2=8^2+10^2 ?

The solutions to the equation x^2=8^2+10^2 are x=2sqrt(41),x=-2sqrt(41)

Find the zeros of x^2=8^2+10^2

The zeros of x^2=8^2+10^2 are x=2sqrt(41),x=-2sqrt(41)

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x^{2} = 8^{2} + 1 0^{2}

x = 241, x = - 241

Solution steps

x^{2} = 8^{2} + 1 0^{2}

Simplify

8^{2} + 1 0^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 164, x = - 164

164 = 241

- 164 = - 241

x = 241, x = - 241

3 (3 x - 2) = (x + 4) (x - 4)

x^{2} - 5 x - 19 = 0

3 x^{2} - 72 = 6 x

X^{2} - 100 = 0

x^{2} + 12 x + 36 = 5

What are the solutions to the equation x^2=8^2+10^2 ?
The solutions to the equation x^2=8^2+10^2 are x=2sqrt(41),x=-2sqrt(41)
Find the zeros of x^2=8^2+10^2
The zeros of x^2=8^2+10^2 are x=2sqrt(41),x=-2sqrt(41)