What are the solutions to the equation x^2+12x+36=5 ?

The solutions to the equation x^2+12x+36=5 are x=-6+sqrt(5),x=-6-sqrt(5)

Find the zeros of x^2+12x+36=5

The zeros of x^2+12x+36=5 are x=-6+sqrt(5),x=-6-sqrt(5)

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x^{2} + 12 x + 36 = 5

x = - 6 + 5, x = - 6 - 5

Solution steps

x^{2} + 12 x + 36 = 5

Move

5

to the left side

x^{2} + 12 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 31 = 25

x_{1, 2} = \frac{- 12 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 5}{2 \cdot 1}

x = \frac{- 12 + 2 5}{2 \cdot 1} : - 6 + 5

x = \frac{- 12 - 2 5}{2 \cdot 1} : - 6 - 5

The solutions to the quadratic equation are:

x = - 6 + 5, x = - 6 - 5

2 x^{2} + 12 x + \frac{35}{2} = 0

5 x^{2} + 7 x + 1 = 0

2 x^{2} + 18 x + 39 = 0

x^{2} + 2 x + 25 = 0

x, x^{2} - 2 x y + y^{2} - 1 = 0

What are the solutions to the equation x^2+12x+36=5 ?
The solutions to the equation x^2+12x+36=5 are x=-6+sqrt(5),x=-6-sqrt(5)
Find the zeros of x^2+12x+36=5
The zeros of x^2+12x+36=5 are x=-6+sqrt(5),x=-6-sqrt(5)