What are the solutions to the equation 5x^2+7x+1=0 ?

The solutions to the equation 5x^2+7x+1=0 are x=(-7+sqrt(29))/(10),x=(-7-sqrt(29))/(10)

Find the zeros of 5x^2+7x+1=0

The zeros of 5x^2+7x+1=0 are x=(-7+sqrt(29))/(10),x=(-7-sqrt(29))/(10)

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5 x^{2} + 7 x + 1 = 0

x = \frac{- 7 + 29}{10}, x = \frac{- 7 - 29}{10}

Decimal Notation

x = - 0.16148 \dots, x = - 1.23851 \dots

Solution steps

5 x^{2} + 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

7^{2} - 4 \cdot 5 \cdot 1 = 29

x_{1, 2} = \frac{- 7 \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 29}{2 \cdot 5}, x_{2} = \frac{- 7 - 29}{2 \cdot 5}

x = \frac{- 7 + 29}{2 \cdot 5} : \frac{- 7 + 29}{10}

x = \frac{- 7 - 29}{2 \cdot 5} : \frac{- 7 - 29}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 29}{10}, x = \frac{- 7 - 29}{10}

2 x^{2} + 18 x + 39 = 0

x^{2} + 2 x + 25 = 0

x, x^{2} - 2 x y + y^{2} - 1 = 0

x^{2} + 21 x = 11 - x^{2}

4 x^{2} - 64 = 8 x - 4

What are the solutions to the equation 5x^2+7x+1=0 ?
The solutions to the equation 5x^2+7x+1=0 are x=(-7+sqrt(29))/(10),x=(-7-sqrt(29))/(10)
Find the zeros of 5x^2+7x+1=0
The zeros of 5x^2+7x+1=0 are x=(-7+sqrt(29))/(10),x=(-7-sqrt(29))/(10)