What are the solutions to the equation x^2+2x+25=0 ?

The solutions to the equation x^2+2x+25=0 are x=-1+2sqrt(6)i,x=-1-2sqrt(6)i

Find the zeros of x^2+2x+25=0

The zeros of x^2+2x+25=0 are x=-1+2sqrt(6)i,x=-1-2sqrt(6)i

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x^{2} + 2 x + 25 = 0

x = - 1 + 26 i, x = - 1 - 26 i

Solution steps

x^{2} + 2 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 25 : 46 i

x_{1, 2} = \frac{- 2 \pm 4 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 6 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 6 i}{2 \cdot 1}

x = \frac{- 2 + 4 6 i}{2 \cdot 1} : - 1 + 26 i

x = \frac{- 2 - 4 6 i}{2 \cdot 1} : - 1 - 26 i

The solutions to the quadratic equation are:

x = - 1 + 26 i, x = - 1 - 26 i

x, x^{2} - 2 x y + y^{2} - 1 = 0

x^{2} + 21 x = 11 - x^{2}

4 x^{2} - 64 = 8 x - 4

x^{2} - 8 x + 1

8 x^{2} - 14 x + 5 = 0

What are the solutions to the equation x^2+2x+25=0 ?
The solutions to the equation x^2+2x+25=0 are x=-1+2sqrt(6)i,x=-1-2sqrt(6)i
Find the zeros of x^2+2x+25=0
The zeros of x^2+2x+25=0 are x=-1+2sqrt(6)i,x=-1-2sqrt(6)i