What are the solutions to the equation x^2+22x=31 ?

The solutions to the equation x^2+22x=31 are x=-11+2sqrt(38),x=-11-2sqrt(38)

Find the zeros of x^2+22x=31

The zeros of x^2+22x=31 are x=-11+2sqrt(38),x=-11-2sqrt(38)

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x^{2} + 22 x = 31

x = - 11 + 238, x = - 11 - 238

Solution steps

x^{2} + 22 x = 31

Move

31

to the left side

x^{2} + 22 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot (- 31) = 438

x_{1, 2} = \frac{- 22 \pm 4 38}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 4 38}{2 \cdot 1}, x_{2} = \frac{- 22 - 4 38}{2 \cdot 1}

x = \frac{- 22 + 4 38}{2 \cdot 1} : - 11 + 238

x = \frac{- 22 - 4 38}{2 \cdot 1} : - 11 - 238

The solutions to the quadratic equation are:

x = - 11 + 238, x = - 11 - 238

24 x^{2} - 14 x - 24 = 0

3 y (y - 6) - 8 = 12

2 x^{2} - 1 = 3 x

8 x^{2} + 2 (x + 6) = 12

x^{2} + 22 x + 117 = 0

What are the solutions to the equation x^2+22x=31 ?
The solutions to the equation x^2+22x=31 are x=-11+2sqrt(38),x=-11-2sqrt(38)
Find the zeros of x^2+22x=31
The zeros of x^2+22x=31 are x=-11+2sqrt(38),x=-11-2sqrt(38)