What are the solutions to the equation 8x^2+2(x+6)=12 ?

The solutions to the equation 8x^2+2(x+6)=12 are x=0,x=-1/4

Find the zeros of 8x^2+2(x+6)=12

The zeros of 8x^2+2(x+6)=12 are x=0,x=-1/4

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8 x^{2} + 2 (x + 6) = 12

x = 0, x = - \frac{1}{4}

Solution steps

8 x^{2} + 2 (x + 6) = 12

Expand

8 x^{2} + 2 (x + 6) : 8 x^{2} + 2 x + 12

8 x^{2} + 2 x + 12 = 12

Move

12

to the left side

8 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

2^{2} - 4 \cdot 8 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 8}, x_{2} = \frac{- 2 - 2}{2 \cdot 8}

x = \frac{- 2 + 2}{2 \cdot 8} : 0

x = \frac{- 2 - 2}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{4}

x^{2} + 22 x + 117 = 0

a, y^{2} + a^{2} = (a + y) 2 - a (a + 1)

x^{2} + 2 x = 15

x^{2} + 8 x - 30 = 18

- x^{2} + 14 x + 94 = 0

What are the solutions to the equation 8x^2+2(x+6)=12 ?
The solutions to the equation 8x^2+2(x+6)=12 are x=0,x=-1/4
Find the zeros of 8x^2+2(x+6)=12
The zeros of 8x^2+2(x+6)=12 are x=0,x=-1/4