What are the solutions to the equation x^2+22x+117=0 ?

The solutions to the equation x^2+22x+117=0 are x=-9,x=-13

Find the zeros of x^2+22x+117=0

The zeros of x^2+22x+117=0 are x=-9,x=-13

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x^{2} + 22 x + 117 = 0

x = - 9, x = - 13

Solution steps

x^{2} + 22 x + 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 117}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 117 = 4

x_{1, 2} = \frac{- 22 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 4}{2 \cdot 1}, x_{2} = \frac{- 22 - 4}{2 \cdot 1}

x = \frac{- 22 + 4}{2 \cdot 1} : - 9

x = \frac{- 22 - 4}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 9, x = - 13

a, y^{2} + a^{2} = (a + y) 2 - a (a + 1)

x^{2} + 2 x = 15

x^{2} + 8 x - 30 = 18

- x^{2} + 14 x + 94 = 0

x^{2} + 7 x - 18 = 0

What are the solutions to the equation x^2+22x+117=0 ?
The solutions to the equation x^2+22x+117=0 are x=-9,x=-13
Find the zeros of x^2+22x+117=0
The zeros of x^2+22x+117=0 are x=-9,x=-13