What are the solutions to the equation x^2+8x-30=18 ?

The solutions to the equation x^2+8x-30=18 are x=4,x=-12

Find the zeros of x^2+8x-30=18

The zeros of x^2+8x-30=18 are x=4,x=-12

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x^{2} + 8 x - 30 = 18

x = 4, x = - 12

Solution steps

x^{2} + 8 x - 30 = 18

Move

18

to the left side

x^{2} + 8 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 48) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 1}, x_{2} = \frac{- 8 - 16}{2 \cdot 1}

x = \frac{- 8 + 16}{2 \cdot 1} : 4

x = \frac{- 8 - 16}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 4, x = - 12

- x^{2} + 14 x + 94 = 0

x^{2} + 7 x - 18 = 0

- 4 x^{2} + x - 1 = 0

8 x^{2} - 20 x = 0

- \frac{23}{40} x^{2} + \frac{1}{2} x + 10 = 0

What are the solutions to the equation x^2+8x-30=18 ?
The solutions to the equation x^2+8x-30=18 are x=4,x=-12
Find the zeros of x^2+8x-30=18
The zeros of x^2+8x-30=18 are x=4,x=-12