What are the solutions to the equation v^2-8v+7=0 ?

The solutions to the equation v^2-8v+7=0 are v=7,v=1

Find the zeros of v^2-8v+7=0

The zeros of v^2-8v+7=0 are v=7,v=1

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v^{2} - 8 v + 7 = 0

v = 7, v = 1

Solution steps

v^{2} - 8 v + 7 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

v_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, v_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

v = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

v = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 7, v = 1

(x - 1)^{2} = 48

5^{2} + y^{2} = 1 3^{2}

x, 4 x - x^{2} y + y^{3} = 10

k^{2} + 5 k = 0

x, y = x^{2} - 9 x + 20

What are the solutions to the equation v^2-8v+7=0 ?
The solutions to the equation v^2-8v+7=0 are v=7,v=1
Find the zeros of v^2-8v+7=0
The zeros of v^2-8v+7=0 are v=7,v=1