What are the solutions to the equation k^2+5k=0 ?

The solutions to the equation k^2+5k=0 are k=0,k=-5

Find the zeros of k^2+5k=0

The zeros of k^2+5k=0 are k=0,k=-5

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k^{2} + 5 k = 0

k = 0, k = - 5

Solution steps

k^{2} + 5 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

k_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 5}{2 \cdot 1}, k_{2} = \frac{- 5 - 5}{2 \cdot 1}

k = \frac{- 5 + 5}{2 \cdot 1} : 0

k = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

k = 0, k = - 5

x, y = x^{2} - 9 x + 20

x^{2} + 3

(5 k - 3) (2 k + 1) = 4, 6 - k (5 k - 3) (2 k + 1) = 46 - k

2 1^{2} + 2 8^{2} = c^{2}

0 = 48 x + 8 x^{2}

What are the solutions to the equation k^2+5k=0 ?
The solutions to the equation k^2+5k=0 are k=0,k=-5
Find the zeros of k^2+5k=0
The zeros of k^2+5k=0 are k=0,k=-5