What are the solutions to the equation r^2+12=0 ?

The solutions to the equation r^2+12=0 are r=2sqrt(3)i,r=-2sqrt(3)i

Find the zeros of r^2+12=0

The zeros of r^2+12=0 are r=2sqrt(3)i,r=-2sqrt(3)i

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r^{2} + 12 = 0

r = 23 i, r = - 23 i

Solution steps

r^{2} + 12 = 0

Move

12

to the right side

r^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 12, r = - - 12

- 12 = 23 i

- - 12 = - 23 i

r = 23 i, r = - 23 i

5 x^{2} - 20 x = 60

x^{2} + 12 x - 6 = 5

x (6 + x) - 2 (x + 1) - 5 x = 4

(x + 9)^{2} = 16

y, 36 x^{2} + 25 y^{2} = 900

What are the solutions to the equation r^2+12=0 ?
The solutions to the equation r^2+12=0 are r=2sqrt(3)i,r=-2sqrt(3)i
Find the zeros of r^2+12=0
The zeros of r^2+12=0 are r=2sqrt(3)i,r=-2sqrt(3)i