What are the solutions to the equation 120x-4.5x^2=0 ?

The solutions to the equation 120x-4.5x^2=0 are x=0,x= 80/3

Find the zeros of 120x-4.5x^2=0

The zeros of 120x-4.5x^2=0 are x=0,x= 80/3

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120 x - 4.5 x^{2} = 0

x = 0, x = \frac{80}{3}

Decimal Notation

x = 0, x = 26.66666 \dots

Solution steps

120 x - 4.5 x^{2} = 0

Multiply both sides by

10

1200 x - 45 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 45 x^{2} + 1200 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1200 \pm 120 0 ^{2} - 4 ( - 45 ) \cdot 0}{2 ( - 45 )}

120 0^{2} - 4 (- 45) \cdot 0 = 1200

x_{1, 2} = \frac{- 1200 \pm 1200}{2 ( - 45 )}

Separate the solutions

x_{1} = \frac{- 1200 + 1200}{2 ( - 45 )}, x_{2} = \frac{- 1200 - 1200}{2 ( - 45 )}

x = \frac{- 1200 + 1200}{2 ( - 45 )} : 0

x = \frac{- 1200 - 1200}{2 ( - 45 )} : \frac{80}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{80}{3}

5 x^{2} - 7 x = 3

5 x^{2} - 7 x = 6

x^{2} - 16 x + 29 = 0

x^{2} + 5 x + c

x^{2} = - 30

What are the solutions to the equation 120x-4.5x^2=0 ?
The solutions to the equation 120x-4.5x^2=0 are x=0,x= 80/3
Find the zeros of 120x-4.5x^2=0
The zeros of 120x-4.5x^2=0 are x=0,x= 80/3