What are the solutions to the equation 3x^2+9x=12 ?

The solutions to the equation 3x^2+9x=12 are x=1,x=-4

Find the zeros of 3x^2+9x=12

The zeros of 3x^2+9x=12 are x=1,x=-4

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3 x^{2} + 9 x = 12

x = 1, x = - 4

Solution steps

3 x^{2} + 9 x = 12

Move

12

to the left side

3 x^{2} + 9 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 12) = 15

x_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 15}{2 \cdot 3}, x_{2} = \frac{- 9 - 15}{2 \cdot 3}

x = \frac{- 9 + 15}{2 \cdot 3} : 1

x = \frac{- 9 - 15}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

2 t^{2} + 9 t - 3 = 0

x^{2} + (x + 1)^{2} + (x + 2)^{2} = - 1

x^{2} - 12 x + 3 = 0

4 x^{2} - 28 x + 53 = 0

x^{2} + 4 x - 2

What are the solutions to the equation 3x^2+9x=12 ?
The solutions to the equation 3x^2+9x=12 are x=1,x=-4
Find the zeros of 3x^2+9x=12
The zeros of 3x^2+9x=12 are x=1,x=-4