What are the solutions to the equation 3(x-1)^2=-27 ?

The solutions to the equation 3(x-1)^2=-27 are x=3i+1,x=-3i+1

Find the zeros of 3(x-1)^2=-27

The zeros of 3(x-1)^2=-27 are x=3i+1,x=-3i+1

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3 (x - 1)^{2} = - 27

x = 3 i + 1, x = - 3 i + 1

Solution steps

3 (x - 1)^{2} = - 27

Divide both sides by

3

(x - 1)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 9 : x = 3 i + 1

Solve

x - 1 = - - 9 : x = - 3 i + 1

The solutions to the quadratic equation are:

x = 3 i + 1, x = - 3 i + 1

- 3 x^{2} + x = 13

1.5 x^{2} + 24 = 0

x, z = x^{2} + 3 x y + y^{2}

1 7^{2} = x^{2} + 1 5^{2}

3 x^{2} = 180

What are the solutions to the equation 3(x-1)^2=-27 ?
The solutions to the equation 3(x-1)^2=-27 are x=3i+1,x=-3i+1
Find the zeros of 3(x-1)^2=-27
The zeros of 3(x-1)^2=-27 are x=3i+1,x=-3i+1