What are the solutions to the equation 13^2+12^2=x^2 ?

The solutions to the equation 13^2+12^2=x^2 are x=sqrt(313),x=-sqrt(313)

Find the zeros of 13^2+12^2=x^2

The zeros of 13^2+12^2=x^2 are x=sqrt(313),x=-sqrt(313)

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1 3^{2} + 1 2^{2} = x^{2}

x = 313, x = - 313

Solution steps

1 3^{2} + 1 2^{2} = x^{2}

Switch sides

x^{2} = 1 3^{2} + 1 2^{2}

Simplify

1 3^{2} + 1 2^{2} : 313

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 313, x = - 313

0 = x^{2} - 13 x + 36

p^{2} - 5 p + 6 = 0

- 3 x^{2} - 12 x = 0

x, 3 x^{2} + y = 3 y^{2} + x

4 x^{2} + 32 x + 236 = - 8

What are the solutions to the equation 13^2+12^2=x^2 ?
The solutions to the equation 13^2+12^2=x^2 are x=sqrt(313),x=-sqrt(313)
Find the zeros of 13^2+12^2=x^2
The zeros of 13^2+12^2=x^2 are x=sqrt(313),x=-sqrt(313)