What are the solutions to the equation p^2-5p+6=0 ?

The solutions to the equation p^2-5p+6=0 are p=3,p=2

Find the zeros of p^2-5p+6=0

The zeros of p^2-5p+6=0 are p=3,p=2

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p^{2} - 5 p + 6 = 0

p = 3, p = 2

Solution steps

p^{2} - 5 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

p_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, p_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

p = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

p = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

p = 3, p = 2

- 3 x^{2} - 12 x = 0

x, 3 x^{2} + y = 3 y^{2} + x

4 x^{2} + 32 x + 236 = - 8

(2 x - 3)^{2} = x + 2 (7 - x^{2})

x^{2} + 144 = 40 x

What are the solutions to the equation p^2-5p+6=0 ?
The solutions to the equation p^2-5p+6=0 are p=3,p=2
Find the zeros of p^2-5p+6=0
The zeros of p^2-5p+6=0 are p=3,p=2