What are the solutions to the equation 3^2+y^2=4 ?

The solutions to the equation 3^2+y^2=4 are y=sqrt(5)i,y=-sqrt(5)i

Find the zeros of 3^2+y^2=4

The zeros of 3^2+y^2=4 are y=sqrt(5)i,y=-sqrt(5)i

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3^{2} + y^{2} = 4

y = 5 i, y = - 5 i

Solution steps

3^{2} + y^{2} = 4

Move

3^{2}

to the right side

y^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 5, y = - - 5

- 5 = 5 i

- - 5 = - 5 i

y = 5 i, y = - 5 i

3^{2} + y^{2} = 9

- x^{2} + 3 x + 7 = 0

5 x^{2} + 3 x = 3

u^{2} = 100

n^{2} - 8 n - 12 = 0

What are the solutions to the equation 3^2+y^2=4 ?
The solutions to the equation 3^2+y^2=4 are y=sqrt(5)i,y=-sqrt(5)i
Find the zeros of 3^2+y^2=4
The zeros of 3^2+y^2=4 are y=sqrt(5)i,y=-sqrt(5)i