What are the solutions to the equation 21^2+b^2=29^2 ?

The solutions to the equation 21^2+b^2=29^2 are b=20,b=-20

Find the zeros of 21^2+b^2=29^2

The zeros of 21^2+b^2=29^2 are b=20,b=-20

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2 1^{2} + b^{2} = 2 9^{2}

b = 20, b = - 20

Solution steps

2 1^{2} + b^{2} = 2 9^{2}

Move

2 1^{2}

to the right side

b^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 400, b = - 400

400 = 20

- 400 = - 20

b = 20, b = - 20

- 2 x^{2} - 7 x + 15 = 0

x^{2} + 4 x + 17 = 8 - 2 x

x, x^{2} - 5 x + 4 = 0

0.75 x^{2} - 1.7 x + 0.5 = 0

14 x^{2} = 3, 5 x = 0

What are the solutions to the equation 21^2+b^2=29^2 ?
The solutions to the equation 21^2+b^2=29^2 are b=20,b=-20
Find the zeros of 21^2+b^2=29^2
The zeros of 21^2+b^2=29^2 are b=20,b=-20