What are the solutions to the equation 6x^2+10=4x ?

The solutions to the equation 6x^2+10=4x are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3

Find the zeros of 6x^2+10=4x

The zeros of 6x^2+10=4x are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 10 = 4 x

x = \frac{1}{3} + i \frac{14}{3}, x = \frac{1}{3} - i \frac{14}{3}

Solution steps

6 x^{2} + 10 = 4 x

Move

4 x

to the left side

6 x^{2} + 10 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 \cdot 10}{2 \cdot 6}

Simplify

(- 4)^{2} - 4 \cdot 6 \cdot 10 : 414 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 14 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 14 i}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 4 14 i}{2 \cdot 6}

x = \frac{- ( - 4 ) + 4 14 i}{2 \cdot 6} : \frac{1}{3} + i \frac{14}{3}

x = \frac{- ( - 4 ) - 4 14 i}{2 \cdot 6} : \frac{1}{3} - i \frac{14}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{14}{3}, x = \frac{1}{3} - i \frac{14}{3}

2 (x + 1)^{2} - 1 = 9

3 n - 6 = 18 n^{2}

3^{2} = x^{2} + 1^{2}

x^{2} + 3 x (x - 12) = 0

3 x^{2} - 12 x + 5

What are the solutions to the equation 6x^2+10=4x ?
The solutions to the equation 6x^2+10=4x are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3
Find the zeros of 6x^2+10=4x
The zeros of 6x^2+10=4x are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3