What are the solutions to the equation 2x^2+2=10 ?

The solutions to the equation 2x^2+2=10 are x=2,x=-2

Find the zeros of 2x^2+2=10

The zeros of 2x^2+2=10 are x=2,x=-2

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2 x^{2} + 2 = 10

x = 2, x = - 2

Solution steps

2 x^{2} + 2 = 10

Move

2

to the right side

2 x^{2} = 8

Divide both sides by

2

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

3 x^{2} - 4 x = - 4

x^{2} - 20 + 12 = 0

0 = 3 x (x - 1) - (3 x + 7)

10 x^{2} + 5 = 1

25 = x^{2} + 14 x + 49

What are the solutions to the equation 2x^2+2=10 ?
The solutions to the equation 2x^2+2=10 are x=2,x=-2
Find the zeros of 2x^2+2=10
The zeros of 2x^2+2=10 are x=2,x=-2